Which is rather to say that x = infinity, or 33/x is 0.
No,
x is just undefined. It is impossible to have infinity as part of the definition-set, thus
x is undefined and the equation is non-solvable. (a/0 != inf and 1/inf != 0, for the reason that inf is not a number, it's a symbol,
x can only be a number, not a symbol)
Other than that rounding the equation without having it IN the equation makes no sense <_<; Frebby can't expect us to solve the unsolvable. If rounding is part of the equation it needs to be in the equation (otherwise, how are we going to know!?). However, doing that just makes in unnecessarily hard and still makes no sense at all. Now I can't see the source code that generated these, but it seems like you are saying the
x always will be undefined, and in that case it's not really "insanely hard" (the answer is just that it's unsolvable,
x is not part of the definition set). Heck, even if
x was part of the definition set it's still just a linear equation, it's the most easiest thing ever. Only constant equation is easier, and that's because it's per definition already solved